Statement : - store the higher nibble of r7 in to both nibbles of r6
Solution: –first we shall get the upper nibble of r7 in r6. Then we swap nibbles of r7 and make OR operation with r6 so the upper and lower nibbles are duplicated
Mov a, r7 ; get the content in acc
Anl a, #0F0h ; mask lower bit
Mov r6, a ; send it to r6
Swap a ; xchange upper and lower nibbles of acc
Orl a, r6 ; OR operation
Mov r6, a ; finally load content in r6
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